{"id":18400,"date":"2024-05-12T06:14:41","date_gmt":"2024-05-12T06:14:41","guid":{"rendered":"https:\/\/soicau3026.minhngocxoso.com\/?p=18400"},"modified":"2024-05-12T06:14:41","modified_gmt":"2024-05-12T06:14:41","slug":"soi-cau-xsmb-voi-cau-day-so-lien-tiep","status":"publish","type":"post","link":"https:\/\/soicaudexsmb.com\/soi-cau-xsmb-voi-cau-day-so-lien-tiep\/","title":{"rendered":"Soi C\u1ea7u XSMB V\u1edbi C\u1ea7u D\u00e3y S\u1ed1 Li\u00ean Ti\u1ebfp"},"content":{"rendered":"
Soi c\u1ea7u XSMB v\u1edbi c\u1ea7u d\u00e3y s\u1ed1 li\u00ean ti\u1ebfp<\/strong> l\u00e0 m\u1ed9t trong nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u XSMB kh\u00e1 hi\u1ec7u qu\u1ea3 v\u00ec c\u00f3 \u0111\u1ed9 ch\u00ednh x\u00e1c kh\u00e1 cao. Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y l\u00e0 c\u00e1ch \u0111\u00e1nh m\u1ed9t c\u1eb7p l\u00f4 max 3 ng\u00e0y \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u c\u00e1c chuy\u00ean gia \u0111\u00e1nh gi\u00e1 cao v\u00ec c\u00f3 \u0111\u1ed9 an to\u00e0n v\u00e0 hi\u1ec7u qu\u1ea3 c\u1ef1c cao. Ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u XSMB v\u1edbi c\u1ea7u d\u00e3y s\u1ed1 li\u00ean ti\u1ebfp n\u00e0y d\u1ef1a tr\u00ean c\u1ea7u, c\u00e1c quy t\u1eafc s\u1ed1 h\u1ecdc v\u00e0 x\u00e1c su\u1ea5t. \u0110\u00e2y l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u c\u00f3 t\u00ednh ch\u1ea5t ph\u1ee9c t\u1ea1p h\u01a1n c\u00e1c ph\u01b0\u01a1ng ph\u00e1p kh\u00e1c r\u1ea5t nhi\u1ec1u. Anh em d\u00e0nh m\u1ed9t ch\u00fat th\u1eddi gian \u0111\u1ec3 \u0111\u1ecdc v\u00e0 nghi\u00ean c\u1ee9u nh\u00e9.<\/p>\n Ti\u1ebfp theo ch\u00fang ta x\u00e9t b\u1ea3ng \u0111\u1ea7u l\u00f4 h\u00f4m nay, v\u00e0 t\u00ecm xem c\u00e1c d\u00e3y s\u1ed1 li\u00ean ti\u1ebfp c\u00f3 2 s\u1ed1 tr\u1edf l\u00ean trong c\u00e1c \u0111\u1ea7u l\u00f4 \u0111\u00f3.<\/p>\n V\u00ed d\u1ee5: <\/b>B\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ng\u00e0y h\u00f4m nay nh\u01b0 sau:<\/p>\n C\u00e1c d\u00e3y s\u1ed1 t\u00ecm th\u1ea5y:<\/b><\/p>\n V\u1edbi nh\u1eefng d\u00e3y s\u1ed1 khoanh tr\u00f2n m\u00e0u \u0111\u1ecf l\u00e0 nh\u1eefng d\u00e3y s\u1ed1 kh\u00f4ng \u0111\u01b0\u1ee3c ch\u1ecdn v\u00ec nh\u1eefng d\u00e3y s\u1ed1 n\u00e0y vi ph\u1ea1m nh\u1eefng quy t\u1eafc sau:<\/strong><\/b><\/p>\n Quy t\u1eafc 1:<\/b> Kh\u00f4ng ch\u1ecdn c\u00e1c d\u00e3y s\u1ed1 li\u00ean ti\u1ebfp \u0111\u1ea7u 0.<\/p>\n V\u00ed d\u1ee5:<\/b> 00 \u2013 01 \u1edf tr\u00ean l\u00e0 \u0111\u1ea7u 0 n\u00ean kh\u00f4ng \u0111\u01b0\u1ee3c ch\u1ecdn.<\/p>\n Quy t\u1eafc 2:<\/b> Kh\u00f4ng ch\u1ecdn c\u00e1c d\u00e3y s\u1ed1 trong c\u00e1c \u0111\u1ea7u l\u00f4 m\u00e0 c\u00f3 5 l\u00f4 tr\u1edf l\u00ean.<\/p>\n V\u00ed d\u1ee5:<\/b> D\u00e3y 45 \u2013 46 \u1edf tr\u00ean, h\u00f4m 24\/1 ra \u0111\u1ebfn 5 l\u00f4 n\u00ean kh\u00f4ng \u0111\u01b0\u1ee3c ch\u1ecdn.<\/p>\n Quy t\u1eafc 3:<\/b> Kh\u00f4ng ch\u1ecdn c\u00e1c d\u00e3y s\u1ed1 trong c\u00e1c \u0111\u1ea7u l\u00f4 m\u00e0 c\u00f3 \u0111\u1ec1 (gi\u1ea3i \u0111\u1eb7c bi\u1ec7t).<\/p>\n V\u00ed d\u1ee5:<\/strong> Theo nh\u01b0 h\u00ecnh tr\u00ean ta c\u00f3 \u0111\u1ec1 v\u1ec1 13 n\u00ean d\u00e3y 18,19 c\u00f9ng \u0111\u1ea7u v\u1edbi \u0111\u1ec1 13 s\u1ebd kh\u00f4ng \u0111\u01b0\u1ee3c ch\u1ecdn.<\/p>\n Quy t\u1eafc 4:<\/b> Kh\u00f4ng ch\u1ecdn c\u00e1c d\u00e3y s\u1ed1 li\u00ean ti\u1ebfp b\u1eaft \u0111\u1ea7u t\u1eeb s\u1ed1 h\u00e0ng ch\u1ee5c.<\/p>\n V\u00ed d\u1ee5:<\/b> \u1ede b\u1ea3ng k\u1ebft qu\u1ea3 tr\u00ean c\u00f3 d\u00e3y s\u1ed1 li\u00ean ti\u1ebfp l\u00e0 70,71. V\u00ec d\u00e3y n\u00e0y b\u1eaft \u0111\u1ea7u t\u1eeb 70 (s\u1ed1 h\u00e0ng ch\u1ee5c) n\u00ean b\u1ecf kh\u00f4ng ch\u1ecdn.<\/p>\n L\u00f4 AB ch\u00ednh l\u00e0 l\u00f4 m\u00e0 ch\u00fang ta c\u1ea7n t\u00ecm \u0111\u1ec3 \u0111\u00e1nh. \u0110\u1ec1 t\u00ecm l\u00f4 AB ch\u00fang ta l\u1ea5y s\u1ed1 \u0111\u1ea7u ti\u00ean c\u1ee7a d\u00e3y s\u1ed1 t\u00ecm \u0111\u01b0\u1ee3c tr\u1eeb \u0111i 1 \u0111\u01a1n v\u1ecb (c\u00f2n g\u1ecdi l\u00e0 s\u1ed1 tr\u01b0\u1edbc d\u00e3y s\u1ed1 \u0111\u00f3 1 \u0111\u01a1n v\u1ecb)<\/p>\n V\u00ed d\u1ee5:<\/b> Nh\u01b0 c\u00e1c d\u00e3y s\u1ed1 t\u00ecm \u0111\u01b0\u1ee3c \u1edf b\u1ea3ng k\u1ebft qu\u1ea3 tr\u00ean tr\u00ean ta t\u00ecm \u0111\u01b0\u1ee3c c\u00e1c AB sau:<\/p>\n (2 d\u00e3y m\u00e0u \u0111\u1ecf \u0111\u00e3 b\u1ecb lo\u1ea1i v\u00ec vi ph\u1ea1m quy t\u1eafc)<\/p>\n \u1ede b\u01b0\u1edbc 2 ch\u00fang ta \u0111\u00e3 t\u00ecm \u0111\u01b0\u1ee3c nhi\u1ec1u AB, tuy nhi\u00ean theo c\u00e1ch soi c\u1ea7u XSMB v\u1edbi c\u1ea7u d\u00e3y s\u1ed1 li\u00ean t\u1ebfp n\u00e0y th\u00ec ta ch\u1ec9 ch\u1ecdn duy nh\u1ea5t 1 AB \u0111\u1ec3 \u0111\u00e1nh 2 l\u00f4 AB v\u00e0 BA v\u00e0o ng\u00e0y h\u00f4m sau. \u0110\u1ec3 t\u00ecm \u0111\u01b0\u1ee3c AB duy nh\u1ea5t c\u00e1c b\u1ea1n l\u00e0m theo 2 b\u01b0\u1edbc sau \u0111\u1ec3 ch\u1ecdn ra AB \u0111\u1eb9p nh\u1ea5t.<\/p>\n Y\u00eau c\u1ea7u 1:<\/b> S\u1ed1 l\u00f4 c\u1ee7a \u0111\u1ea7u A c\u1ed9ng v\u1edbi s\u1ed1 l\u00f4 c\u1ee7a \u0111\u1ea7u B ph\u1ea3i \u00edt h\u01a1n 8 l\u00f4.<\/p>\n V\u00ed d\u1ee5:<\/b> Theo nh\u01b0 b\u1ea3ng k\u1ebft qu\u1ea3 tr\u00ean t\u1eeb d\u00e3y s\u1ed1 51 \u2013 52 ta t\u00ecm \u0111\u01b0\u1ee3c AB = 50. Ch\u00fang ta th\u1ea5y \u0111\u1ea7u 5 c\u00f3 4 l\u00f4 l\u00e0 51-52-55-56. \u0110\u1ea7u 0 c\u00f3 4 l\u00f4 00-00-03-05. Th\u00ec t\u1ed5ng l\u1ea1i l\u00e0 c\u00f3 8 l\u00f4. M\u00e0 y\u00eau c\u1ea7u ph\u1ea3i \u00edt h\u01a1n 8 l\u00f4 => AB = 50 Lo\u1ea1i.<\/p>\n Y\u00eau c\u1ea7u 2: <\/b>Khi l\u1ed9n l\u00f4 AB ta th\u1ea5y l\u00f4 BA ng\u00e0y h\u00f4m \u0111\u00f3 v\u1ec1 2 nh\u00e1y tr\u1edf l\u00ean => Lo\u1ea1i.<\/p>\n V\u00ed d\u1ee5: <\/b>V\u1edbi k\u1ebft qu\u1ea3 \u1edf b\u1ea3ng tr\u00ean ta c\u00f3 d\u00e3y 93 \u2013 94 th\u00ec ta t\u00ecm \u0111\u01b0\u1ee3c AB = 92. Nh\u01b0ng khi l\u1ed9n ta th\u1ea5y l\u00f4 29 ng\u00e0y h\u00f4m \u0111\u00f3 v\u1ec1 2 nh\u00e1y. V\u1eady AB = 92 Lo\u1ea1i.<\/p>\n Y\u00eau c\u1ea7u 3:<\/b> T\u00ecm \u0111\u01b0\u1ee3c AB m\u00e0 B l\u1ea1i l\u00e0 \u0111\u1ea7u s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t (\u0110\u1ec1). => Lo\u1ea1i.<\/p>\n V\u00ed d\u1ee5:<\/b> V\u1edbi b\u1ea3ng k\u1ebft qu\u1ea3 tr\u00ean ch\u00fang ta c\u00f3 d\u00e3y 46 \u2013 47 th\u00ec AB = 45. Ta th\u1ea5y \u0111\u1ec1 h\u00f4m \u0111\u00f3 v\u1ec1 56. M\u00e3 AB = 45 c\u00f3 5 tr\u00f9ng v\u1edbi \u0111\u1ea7u c\u1ee7a \u0111\u1ec1 56 => AB = 45 Lo\u1ea1i.<\/p>\n Sau khi x\u00e9t qua c\u00e1c y\u00eau c\u1ea7u c\u1ee7a AB tr\u00ean m\u00e0 v\u1eabn \u0111ang c\u00f2n nhi\u1ec1u h\u01a1n 1 AB th\u00ec ch\u00fang ta v\u1eadn d\u1ee5ng c\u00e1c Lu\u1eadt \u01b0u ti\u00ean du\u1edbi \u0111\u00e2y \u0111\u1ec3 ch\u1ecdn ra AB c\u1ea7n \u0111\u00e1nh.<\/p>\n Lu\u1eadt \u01b0u ti\u00ean 1:<\/b> \u01afu ti\u00ean nh\u1eefng con AB m\u00e0 c\u00f3 con l\u00f4 b\u00e9 h\u01a1n g\u1ea7n nh\u1ea5t v\u1edbi n\u00f3 c\u00f3 c\u00f9ng \u0111\u1ea7u A. Ngh\u0129a l\u00e0 c\u00f3 l\u00f4 ch\u1eb7n \u0111\u1ea7u.<\/p>\n V\u00ed d\u1ee5:<\/b> Ta th\u1ea5y AB = 91 v\u00e0 AB = 72 kh\u00f4ng c\u00f3 con l\u00f4 n\u00e0o c\u00f9ng \u0111\u1ea7u m\u00e0 b\u00e9 h\u01a1n xu\u1ea5t hi\u1ec7n.<\/p>\n N\u00ean ta s\u1ebd \u01b0u ti\u1ec1n AB = 35 c\u00f3 l\u00f4 31 l\u00e0 l\u00f4 c\u00f9ng \u0111\u1ea7u b\u00e9 h\u01a1n \u0111\u1ee9ng tr\u01b0\u1edbc n\u00f3.<\/p>\n Lu\u1eadt \u01b0u ti\u00ean 2:<\/b> \u01afu ti\u00ean nh\u1eefng con AB m\u00e0 hi\u1ec7u gi\u1eefa AB v\u00e0 con l\u00f4 b\u00e9 h\u01a1n g\u1ea7n nh\u1ea5t trong kho\u1ea3ng 3,4,5 \u0111\u01a1n v\u1ecb (3,4,5 coi nh\u01b0 t\u01b0\u01a1ng \u0111\u01b0\u01a1ng nhau trong \u01b0u ti\u00ean) h\u01a1n t\u1ea5t c\u1ea3 c\u00e1c hi\u1ec7u kh\u00e1c.<\/p>\n \u0110\u1eb7c bi\u1ec7t:<\/b> Lu\u1eadt n\u00e0y v\u1eabn \u0111\u00fang khi AB l\u00e0 k\u00e9p.<\/p>\n V\u00ed d\u1ee5:<\/b> Gi\u1ea3 s\u1eed nh\u01b0 k\u1ebft qu\u1ea3 tr\u00ean, ta t\u00ecm \u0111\u01b0\u1ee3c c\u00e1c d\u00e3y 28,29 v\u00e0 d\u00e3y 87,88 l\u00e0 c\u00f3 1 con nh\u1ecf c\u00f9ng \u0111\u1ea7u \u0111\u1ee9ng tr\u01b0\u1edbc.<\/p>\n Lu\u1eadt \u01b0u ti\u00ean 3:<\/b> N\u1ebfu \u0111\u1ec1u l\u00e0 l\u00f4 ch\u1eb7n \u0111\u1ea7u th\u00ec \u01b0u ti\u00ean nh\u1eefng con AB c\u00f3 hi\u1ec7u gi\u1eefa AB v\u00e0 con l\u00f4 b\u00e9 h\u01a1n g\u1ea7n nh\u1ea5t trong kho\u1ea3ng (2,6,7) h\u01a1n l\u00e0 hi\u1ec7u = 1.<\/p>\n \u0110\u1eb7c bi\u1ec7t: <\/b>N\u1ebfu AB l\u00e0 k\u00e9p th\u00ec s\u1ebd \u01b0u ti\u00ean hi\u1ec7u = 1 h\u01a1n.<\/p>\n V\u00ed d\u1ee5: <\/b>Ch\u01b0a c\u00f3 ti\u1ec1n \u0111\u1ec1 n\u00e0o th\u1ef1c t\u1ebf \u0111\u1ec3 v\u00ed d\u1ee5 \u01b0u ti\u00ean n\u00e0y. N\u00ean m\u00ecnh s\u1ebd l\u1ea5y v\u00ed d\u1ee5 c\u00f3 2 \u0111\u1ea7u l\u00f4 ra nh\u01b0 sau.<\/p>\n Lu\u1eadt \u01b0u ti\u00ean 4:<\/b> G\u1ecdi hi\u1ec7u gi\u1eefa AB v\u00e0 con l\u00f4 b\u00e9 h\u01a1n g\u1ea7n nh\u1ea5t = X th\u00ec hi\u1ec7u X c\u00e0ng c\u00e1ch xa kho\u1ea3ng (3,4,5) th\u00ec c\u00e0ng kh\u00f4ng \u01b0u ti\u00ean. ( X=2 v\u00e0 X=6 l\u00e0 t\u01b0\u01a1ng \u0111\u01b0\u01a1ng nhau)<\/p>\n V\u00ed d\u1ee5:<\/b> Theo k\u1ebft qu\u1ea3 tr\u00ean ta c\u00f3 2 d\u00e3y 74-75-76-77 v\u00e0 d\u00e3y 53-54 Th\u00ec ta t\u00ecm \u0111\u01b0\u1ee3c AB = 73 v\u00e0 AB = 52. Hi\u1ec7u v\u1edbi l\u00f4 g\u1ea7n nh\u1ea5t l\u1ea7n l\u01b0\u1ee3t l\u00e0 X = 12 v\u00e0 X = 10. V\u1eady X = 10 s\u1ebd \u0111\u01b0\u1ee3c \u01b0u ti\u1ec1n h\u01a1n (v\u00ec g\u1ea7n kho\u1ea3ng 3,4,5). N\u00ean ta ch\u1ecdn AB = 52.<\/p>\n Lu\u1eadt \u01b0u ti\u00ean 5:<\/b> N\u1ebfu hi\u1ec7u X \u1edf c\u00e1c v\u1ecb tr\u00ed t\u01b0\u01a1ng \u0111\u01b0\u01a1ng nhau th\u00ec ta \u01b0u ti\u00ean \u0111\u1ea7u l\u00f4 c\u1ee7a A n\u00e0o g\u1ea7n v\u1edbi \u0111\u1ea7u c\u1ee7a \u0110\u1ec1 nh\u1ea5t. N\u1ebfu kho\u1ea3ng c\u00e1ch v\u1edbi \u0111\u1ec1 nh\u01b0 nhau th\u00ec ch\u1ecdn AB n\u00e0o c\u00f3 A l\u1edbn h\u01a1n.<\/p>\n V\u00ed d\u1ee5 1: <\/b>Ta t\u00ecm \u0111\u01b0\u1ee3c d\u00e3y 27 \u2013 28 v\u00e0 d\u00e3y 96 \u2013 97. Th\u00ec c\u00e1c d\u00e3y n\u00e0y \u0111\u1ec1u c\u00f3 X = 5, 3. \u0110\u1ec1u \u0111\u01b0\u1ee3c \u01b0u ti\u00ean. M\u00e0 \u0111\u1ec1 h\u00f4m \u0111\u00f3 v\u1ec1 \u0111\u1ea7u 0. N\u00ean ta ch\u1ecdn d\u00e3y g\u1ea7n \u0111\u1ec1 h\u01a1n l\u00e0 27 \u2013 28. N\u00ean AB l\u00e0 26.<\/p>\n V\u00ed d\u1ee5 2:<\/b> Ta t\u00ecm \u0111\u01b0\u1ee3c d\u00e3y 68,69 v\u00e0 d\u00e3y 26,27. \u0110\u1ec1u c\u00f3 hi\u1ec7u X =4 v\u00e0 X = 3. M\u00e0 \u0111\u1ec1 h\u00f4m \u0111\u00f3 v\u1ec1 \u0111\u1ea7u 4. M\u00e0 \u0111\u1ea7u 2 v\u1edbi \u0111\u1ea7u 6 th\u00ec kho\u1ea3ng c\u00e1ch v\u1edbi \u0111\u1ea7u 4 l\u00e0 nh\u01b0 nhau. N\u00ean v\u1eadn d\u1ee5ng lu\u1eadt \u01b0u ti\u00ean n\u00e0y ta ch\u1ecdn d\u00e3y l\u1edbn h\u01a1n. N\u00ean AB = 67.<\/p>\n Nh\u01b0 v\u1eady nh\u1edd v\u00e0o lu\u1eadt \u01b0u ti\u00ean tr\u00ean c\u00e1c b\u1ea1n s\u1ebd ch\u1ecdn \u0111\u01b0\u1ee3c m\u1ed9t con AB \u01b0ng \u00fd nh\u1ea5t ng\u00e0y h\u00f4m \u0111\u00f3.<\/p>\n M\u00ecnh xin t\u00f3m t\u1eaft l\u1ea1i c\u00e1c lu\u1eadt \u01b0u ti\u00ean ( X l\u00e0 hi\u1ec7u c\u1ee7a AB v\u1edbi l\u00f4 b\u00e9 h\u01a1n g\u1ea7n nh\u1ea5t):<\/b><\/p>\n Khi t\u00ecm \u0111\u01b0\u1ee3c AB c\u00e1c b\u1ea1n s\u1ebd \u0111\u00e1nh AB, BA v\u00e0o ng\u00e0y h\u00f4m sau. V\u00e0 \u0111\u00e1nh max 3 ng\u00e0y, ngh\u0129a l\u00e0 n\u1ebfu ng\u00e0y mai b\u1ea1n tr\u00fang th\u00ec b\u1ea1n s\u1ebd t\u00ednh c\u1ea7u m\u1edbi \u0111\u00e1nh, n\u1ebfu tr\u01b0\u1ee3t b\u1ea1n s\u1ebd theo hai con AB, BA \u0111\u00f3 v\u00e0o ng\u00e0y kia n\u1eefa. N\u1ebfu \u0111\u00e1nh 2 ng\u00e0y tr\u01b0\u1ee3t th\u00ec b\u1ecf ngay.<\/p>\n Ch\u00fa \u00fd:<\/b> C\u1ea7u n\u00e0y l\u00e0 c\u1ea7u h\u00e0ng ng\u00e0y n\u00ean ng\u00e0y n\u00e0o xu\u1ea5t hi\u1ec7n c\u1ea7u c\u1ee9 \u0111\u00e1nh. Nhi\u1ec1u anh em s\u1ebd h\u1ecfi l\u00e0 n\u1ebfu \u0111\u00e1nh tr\u01b0\u1ee3t th\u00ec ng\u00e0y h\u00f4m sau \u0111\u00e1nh l\u1ea1i, nh\u01b0ng c\u00f3 \u0111\u00e1nh th\u00eam 2 l\u00f4 t\u00ednh v\u1eeba t\u00ednh th\u00eam ng\u00e0y h\u00f4m \u0111\u00f3 kh\u00f4ng. Th\u00ec l\u1eddi khuy\u00ean anh em c\u1ee9 theo c\u1ea7u v\u00e0 \u0111\u00e1nh c\u1ea3 4 l\u00f4 c\u1ea7n \u0111\u00e1nh.<\/p>\n Tr\u01b0\u1eddng h\u1ee3p 1:<\/b> AB ho\u1eb7c BA l\u00e0 l\u00f4 khan th\u00ec b\u1ecf l\u00f4 khan \u0111\u00f3 ch\u1ec9 \u0111\u00e1nh l\u00f4 kh\u00f4ng khan. (L\u00f4 khan l\u00e0 l\u00f4 kh\u00f4ng ra t\u1eeb 10 ng\u00e0y tr\u1edf l\u00ean)<\/p>\n V\u00ed d\u1ee5:<\/b> Ch\u00fang ta t\u00ecm ra AB = 46. M\u00e0 con BA = 64 \u0111ang l\u00e0 l\u00f4 khan 13 ng\u00e0y n\u00ean kh\u00f4ng \u0111\u00e1nh 64 m\u00e0 ch\u1ec9 \u0111\u00e1nh 46. V\u00e0 c\u1ea7u n\u00e0y b\u1ecb g\u00e3y, nh\u01b0ng \u0111\u00e1nh 1 con n\u00ean c\u0169ng \u0111\u1ee1 l\u1ed7 h\u01a1n nhi\u1ec1u.<\/p>\n Tr\u01b0\u1eddng h\u1ee3p 2:<\/b> \u0110\u00e2y ch\u1eb3ng ph\u1ea3i l\u00e0 tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t m\u00e0 m\u00ecnh s\u1ebd n\u00f3i cho b\u1ea1n nh\u1eefng c\u1ea7u n\u00e0o c\u00f3 x\u00e1c su\u1ea5t ra cao nh\u1ea5t.<\/p>\n <\/b>C\u1ea7u d\u1ec5 ra:<\/b> AB c\u00f3 ch\u1eb7n \u0111\u1ea7u. Hi\u1ec7u X = 3,4,5.<\/p>\n <\/b>C\u1ea7u x\u1ea5u nh\u1ea5t:<\/b> C\u1ea7u n\u00e0y c\u00f3 th\u1ec3 \u0111\u00e1nh b\u00ecnh th\u01b0\u1eddng, nh\u01b0ng n\u00f3 l\u00e0 nh\u1eefng c\u1ea7u x\u1ea5u nh\u1ea5t.<\/p>\n Soi c\u1ea7u XSMB v\u1edbi c\u1ea7u d\u00e3y s\u1ed1 li\u00ean ti\u1ebfp<\/strong> l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u kh\u00e1 ph\u1ee9c t\u1ea1p. Anh em n\u00ean tham kh\u1ea3o th\u1eadt k\u1ef9 c\u00e1ch soi \u0111\u1ec3 c\u00f3 th\u1ec3 t\u00ecm ra cho m\u00ecnh c\u1eb7p l\u00f4 ch\u00ednh x\u00e1c nh\u1ea5t trong ng\u00e0y. Ngo\u00e0i ra anh em h\u00e3y t\u1ef1 soi theo ph\u01b0\u01a1ng ph\u00e1p n\u00e0y v\u00e0 \u0111\u1ed1i chi\u1ebfu v\u1edbi k\u1ebft qu\u1ea3 m\u00ecnh soi \u1edf ph\u1ea7n d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 h\u00e0ng ng\u00e0y. N\u1ebfu c\u00f3 v\u1ea5n \u0111\u1ec1 g\u00ec th\u1eafc m\u1eafc anh em c\u1ee9 \u0111\u1eb7t c\u00e2u h\u1ecfi, m\u00ecnh s\u1ebd gi\u1ea3i \u0111ap ngay khi c\u00f3 th\u1ec3.<\/p>\nI. H\u01b0\u1edbng d\u1eabn soi c\u1ea7u XSMB v\u1edbi c\u1ea7u d\u00e3y s\u1ed1 li\u00ean ti\u1ebfp<\/h2>\n
B\u01b0\u1edbc 1: T\u00ecm c\u00e1c d\u00e3y li\u00ean ti\u1ebfp<\/b><\/h3>\n
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B\u01b0\u1edbc 2: T\u00ecm c\u00e1c l\u00f4 AB<\/b><\/h3>\n
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B\u01b0\u1edbc 3: Ch\u1ecdn AB<\/b><\/h3>\n
1. C\u00e1c y\u00eau c\u1ea7u c\u1ee7a AB<\/h4>\n
2. L\u1ef1a ch\u1ecdn AB<\/h4>\n
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B\u01b0\u1edbc 4: \u0110\u00e1nh l\u00f4<\/b><\/h3>\n
II. Nh\u1eefng tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t soi c\u1ea7u XSMB v\u1edbi c\u1ea7u d\u00e3y s\u1ed1 li\u00ean ti\u1ebfp<\/b><\/h2>\n
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